y=1/2(5-4x-x^2)

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Solution for y=1/2(5-4x-x^2) equation: 


x in (-oo:+oo)

y = (1/2)*(5-x^2-(4*x)) // - (1/2)*(5-x^2-(4*x))

y-((1/2)*(5-x^2-(4*x))) = 0

(-1/2)*(5-x^2-4*x)+y = 0

y-1/2*(5-x^2-4*x) = 0

y-1/2*(5-x^2-4*x) = 0

1/2*x^2+2*x+y-5/2 = 0

1/2*x^2+2*x+y-5/2 = 0

1/2*x^2+2*x+y-5/2 = 0

DELTA = 2^2-(1/2*4*(y-5/2))

DELTA = 4-2*(y-5/2)

4-2*(y-5/2) = 0

4-2*(y-5/2) = 0

9-2*y = 0

9-2*y = 0

9-2*y = 0 // - 9

-2*y = -9 // : -2

y = -9/(-2)

y = 9/2

DELTA = 0  <=>  t_3 = 9/2

x = -2/(1/2*2) i y = 9/2

x = -2 i y = 9/2

( x = ((4-2*(y-5/2))^(1/2)-2)/(1/2*2) or x = (-(4-2*(y-5/2))^(1/2)-2)/(1/2*2) ) i y > 9/2

( x = (4-2*(y-5/2))^(1/2)-2 or x = -((4-2*(y-5/2))^(1/2)+2) ) i y > 9/2

y-9/2 > 0

y-9/2 > 0 // + 9/2

y > 9/2

x in { -2, (4-2*(y-5/2))^(1/2)-2, -((4-2*(y-5/2))^(1/2)+2) }

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